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函数积分十:二重积分的计算

定理1

如果\(f\)\(I = [a,b] \times [c,d]\)上可积,那么单变量函数\(\displaystyle \varphi(x) = \underline \int_c^d f(x, y) \mathrm{d} y\)\(\displaystyle \psi(x) = \overline \int_c^d f(x, y) \mathrm{d} y\)在区间\([a,b]\)上可积,且
\[ \int_I f \mathrm{d} \sigma = \int_a^b \varphi(x) \mathrm{d} x = \int_a^b \psi(x) \mathrm{d} x \]

证:分别对\([a,b]\)\([c,d]\)的分割
\[ \begin{aligned} \pi_x: a = x_0 < x_1 < \cdots < x_n = b, \\ \pi_y: c = y_0 < y_1 < \cdots < y_m = d, \end{aligned} \]

\[ \begin{aligned} & I_i = [x_{i-1}, x_i] \quad (i=1,2,\cdots,n) \\ & J_j = [y_{j-1}, y_j] \quad (j=1,2,\cdots,m) \end{aligned} \]
则子矩形
\[ I_i \times I_j \quad (i=1,2,\cdots,n; j=1,2,\cdots,m) \]
形成了矩形\(I\)的分割\(\pi = \pi_x \times \pi_y\)。令\(\displaystyle A = \int_I f \mathrm{d} \sigma\),由积分存在的定义可知,对任意的\(\varepsilon > 0\),存在\(\delta > 0\),当\(I\)的分割\(\pi\)满足\(\Vert \pi \Vert < \delta\)时,必有
\[ A - \varepsilon < \sum_{i=1}^n \sum_{j=1}^m f(\xi_i, \eta_j) \Delta x_i \Delta y_j < A + \varepsilon \]
其中\(\xi_i \in I_i, \eta_j \in J_j (i=1,2,\cdots,n;j=1,2,\cdots,m)\),现取分割\(\pi_x, \pi_y\)满足\(\Vert \pi_x \Vert < \delta / \sqrt 2, \Vert \pi_y \Vert < \delta / \sqrt 2\),那么\(\Vert \pi \Vert < \delta\),从而上式成立,所以有
\[ \begin{aligned} A - \varepsilon &\le \sum_{i=1}^n \sum_{j=1}^m \inf f(\xi_i, \eta_j) \Delta x_i \Delta y_j \\ & \le \sum_{i=1}^n \sum_{j=1}^m \sup f(\xi_i, \eta_j) \Delta x_i \Delta y_j \\ & \le A + \varepsilon \end{aligned} \]
\(\displaystyle \sum_{j=1}^m \inf f(\xi_i, \eta_j) \Delta y_j\)表示函数\(f(\xi_i)\)\([c,d]\)上的下和,所以
\[ \sum_{j=1}^m \inf f(\xi_i, \eta_j) \Delta y_j \le \underline \int_c^d f(\xi_i, y) \mathrm{d} y = \varphi(\xi_i) \]
同理
\[ \sum_{j=1}^m \sup f(\xi_i, \eta_j) \Delta y_j \le \overline \int_c^d f(\xi_i, y) \mathrm{d} y = \psi(\xi_i) \]
从而
\[ A - \varepsilon \le \sum_{i=1}^n \varphi(\xi_i) \Delta x_i \le \sum_{i=1}^n \psi(\xi_i) \Delta x_i \le A + \varepsilon \]

\[ \lim_{\Vert \pi_x \Vert \to 0} \sum_{i=1}^n \varphi(\xi_i) \Delta x_i = \lim_{\Vert \pi \Vert \to 0} \sum_{i=1}^n \psi(\xi_i) \Delta x_i = A \]
成立

Q.E.D.

定理2

\(f\)\(I = [a,b] \times [c, d]\)上可积,如果对每一个\(x \in [a,b]\),函数\(f(x, y)\)\([c, d]\)上可积,则
\[ \int_I f \mathrm{d} \sigma = \int_a^b \left(\int_c^d f(x, y) \mathrm{d} y \right) \mathrm{d} x \]
上面等式右边称为累次积分,也可以记为
\[ \int_a^b \mathrm{d} x \int_c^d f(x, y) \mathrm{d} y \]
同样,如果对于每一个\(y \in [c, d]\),函数\(f(x, y)\)\([a,b]\)上可积,那么有
\[ \int_I f \mathrm{d} \sigma = \int_c^d \left(\int_a^b f(x, y) \mathrm{d} x \right) \mathrm{d} y \]
上面等式右边也可以记为
\[ \int_c^d \mathrm{d} y \int_a^b f(x, y) \mathrm{d} x \]

证:由定理1可知,
\[ \varphi(x) = \psi(x) = \int_c^d f(x, y) \mathrm{d} y \]
所以
\[ \int_I f \mathrm{d} \sigma = \int_a^b \varphi(x) \mathrm{d} x = \int_a^b \mathrm{d} x \int_c^d f(x, y) \mathrm{d} y \]
后半部分同样的证明方法。

Q.E.D.

定理3

\(f\)\([a,b] \times [c, d]\)上的连续函数,则有
\[ \int_c^d \mathrm{d} y \int_a^b f(x, y) \mathrm{d} x = \int_a^b \mathrm{d} x \int_c^d f(x, y) \mathrm{d} y \]

证:由于\(f\)连续,从而\(\varphi(x)\)\(\psi(x)\)都可积,再由定理2易证。

Q.E.D.

定理4

设点集
\[ B = \{(x, y): y_1(x) \le y \le y_2(x), a \le x \le b\} \]
其中函数\(y_1,y_2\)\([a,b]\)上连续,函数\(f\)\(B\)上可积。如果对任意的\(x \in [a,b]\),单变量积分
\[ \int_{y_1(x)}^{y_2(x)} f(x, y) \mathrm{d} y \]
存在,那么
\[ \int_B f \mathrm{d} \sigma = \int_a^b \mathrm{d} x \int_{y_1(x)}^{y_2(x)} f(x, y) \mathrm{d} y \]

证:令\(c = \inf y_1([a, b]), d = \sup y_2([a, b])\),从而\(I = [a, b] \times [c, d] \supset B\),由于\(f\)\(B\)上可积,从而\(f_B\)\(I\)上可积,而且
\[ \int_B f \mathrm{d} \sigma = \int_I f_B \mathrm{d} \sigma \]
显然易知,对每一个\(x \in [a,b]\)\(f_B(x, y)\)\([c, d]\)上可积,所以由定理2可知,
\[ \int_I f_B \mathrm{d} \sigma = \int_a^b \mathrm{d} x \int_c^d f_B(x, y) \mathrm{d} y = \int_a^b \mathrm{d} x \int_{y_1(x)}^{y_2(x)} f_B \mathrm{d} y = \int_a^b \mathrm{d} x\int_{y_1(x)}^{y_2(x)} f(x, y) \mathrm{d} y \]

Q.E.D.

定义1:正则映射

设有界闭域\(D \subset \mathbb{R}^2\),连续函数\(F: D \to \mathbb{R}\),映射\(\boldsymbol{\varphi}\)由公式
\[ x = x(u, v), \quad y = y(u, v) \quad ((u, v) \in \Delta) \]
定义,其中\(\Delta\)\(uv\)平面上的有界闭区域,设映射\(\boldsymbol{\varphi}\)是正则的,即\(\boldsymbol{\varphi}\)是从\(\Delta\)\(D\)上的一对一的映射,\(\boldsymbol{\varphi}\)\(\Delta\)上连续可导,并且
\[ \frac{\partial (x, y) }{\partial (u, v)} = \begin{vmatrix} \frac{\partial x}{\partial u} & \frac{\partial x}{\partial v} \\ \frac{\partial y}{\partial u} & \frac{\partial y}{\partial v} \end{vmatrix} \neq 0 \]
\(\Delta\)上成立。

定理5

设正则映射\(\boldsymbol{\varphi}\)\(\mathbb{R}^2\)中以
\[ (u_0, v_0), \quad (u_0 + h, v_0), \quad (u_0+h, v_0 +h), \quad (u_0, v_0 +h) \]
为顶点的的矩形\(A_{hk}\)一对一的映射为\(\boldsymbol{\varphi}(A_{hk})\),那么
\[ \lim \limits_{ h\to 0, k \to 0} \frac{\sigma(\boldsymbol{\varphi}(A_{hk}))}{\sigma(A_{hk})} = \left| \frac{\partial(x, y)}{\partial(u, v)} \right|_{(u_0, v_0)} \]

证:由映射后的图像有
\[ \sigma(\boldsymbol{\varphi}(A_{hk})) \approx \Vert (\boldsymbol{\varphi}(u_0 + h, v_0) - \boldsymbol{\varphi}(u_0, v_0)) \times (\boldsymbol{\varphi}(u_0, v_0 + k) - \boldsymbol{\varphi}(u_0, v_0)) \Vert \]
由于
\[ \begin{aligned} \boldsymbol{\varphi}(u_0 + h, v_0) - \boldsymbol{\varphi}(u_0, v_0) = \frac{\partial \boldsymbol{\varphi}}{\partial u} (u_0, v_0) h + \boldsymbol{\xi} \\ \boldsymbol{\varphi}(u_0, v_0+h) - \boldsymbol{\varphi}(u_0, v_0) = \frac{\partial \boldsymbol{\varphi}}{\partial v} (u_0, v_0) h + \boldsymbol{\eta} \end{aligned} \]
其中
\[ \Vert \boldsymbol{\xi} \Vert = o(h), \quad \Vert \boldsymbol{\eta} \Vert = o(k) \]
所以
\[ \sigma(\boldsymbol{\varphi}(A_{hk})) \approx \Vert \frac{\partial \boldsymbol{\varphi}}{\partial u}(u_0, v_0) \times \frac{\partial \boldsymbol{\varphi}}{\partial v}(u_0, v_0) \Vert hk + o(hk) \]

\[ hk = \sigma(A_{hk}) \]
所以上式可以写为
\[ \frac{\sigma (\boldsymbol{\varphi}(A_{hk}))}{\sigma(A_{hk})} \approx \Vert \frac{\partial \boldsymbol{\varphi}}{\partial u}(u_0, v_0) \times \frac{\partial \boldsymbol{\varphi}}{\partial v}(u_0, v_0) \Vert + o(1) \]
又因为
\[ \frac{\partial \boldsymbol{\varphi}}{\partial u} \times \frac{\partial \boldsymbol{\varphi}}{\partial v} = \left| \begin{matrix} \boldsymbol{i} & \boldsymbol{j} & \boldsymbol{k}\\ \frac{\partial x}{\partial u} & \frac{\partial x}{\partial v} & 0 \\ \frac{\partial y}{\partial u} & \frac{\partial y}{\partial v} & 0 \\ \end{matrix} \right| = \frac{\partial(x, y)}{\partial(u, v)} \boldsymbol{k} \]
所以
\[ \Vert \frac{\partial \boldsymbol{\varphi}}{\partial u} \times \frac{\partial \boldsymbol{\varphi}}{\partial v} \Vert = \left| \frac{\partial (x, y)}{\partial(u, v)} \right| \]
从而
\[ \frac{\sigma (\boldsymbol{\varphi}(A_{hk}))}{\sigma(A_{hk})} \approx \left| \frac{\partial(x, y)}{\partial(u, v)} \right|_{(u_0, v_0)} + o(hk) \]
所以当\(h \to 0, k \to 0\)时,有
\[ \frac{\sigma (\boldsymbol{\varphi}(A_{hk}))}{\sigma(A_{hk})} = \left| \frac{\partial(x, y)}{\partial(u, v)} \right|_{(u_0, v_0)} \]

笔者注:感觉该证明方法不太好,约等于记号不应该用在这里,就算使用也应该讲明原因。

Q.E.D.

定理6

\(\mathbb{R}^2\)中的有界闭区域\(D\)有面积,函数\(F: \to \mathbb{R}\),映射
\[ \boldsymbol{\varphi}: \left\{ \begin{aligned} x = x(u, v) \\ y = y(u, v) \end{aligned} \right. \quad (u, v) \in \Delta \]
是从\(\Delta\)\(D\)上的正则映射,那么
\[ \iint \limits_D F(x, y) \mathrm{d} x \mathrm{d} y = \iint \limits_\Delta F \circ \boldsymbol{\varphi}(u, v) \left| \frac{\partial(x, y)}{\partial(u, v)} \right| \mathrm{d} u \mathrm{d} v \]

证:用矩形\(I\)\(uv\)平面上的闭区域\(\Delta\)覆盖起来,用两族平行直线\(u =u_i (i=0,1,2, \cdots, m)\)\(v = v_j (j=0,1,2, \cdots,n)\)分割\(I\),其中
\[ u_0 < u_1 < \cdots < u_{m-1} < u_m, \quad v_0 < v_1 < \cdots < v_{n-1} < v_n \]
\(\Delta u_i = u_i - u_{i-1}(i=1,2,\cdots,m), \Delta v_j = v_j - v_{j-1}(j=1,2,\cdots,n)\)。分割后可以得到\(mn\)个矩形,在映射\(\boldsymbol{\varphi}\)的作用下,它们变成了\(xy\)平面下的\(mn\)个曲边平行四边形,这时只需要考虑那些完全被包含在\(D\)中的曲边平行四边形,将它们记为\(D_i(i=1,2,\cdots,k)\),即\(D_i=\boldsymbol{\varphi}(\Delta_i)\),其中\(\Delta_i(i=1,2,\cdots,k)\)是完全被包含在\(\Delta\)中的矩形,任取一点\(\boldsymbol{\eta}_i \in D_i\) ,并设\(\Delta_i\)中唯一的点\(\xi_i\),使得\(\boldsymbol{\varphi} (\xi_i) = \eta_i(i=1,2,\cdots,k)\),作积分和
\[ \sum_{i=1}^k F(\boldsymbol{\eta}_i) \sigma(D_i) \]
定理5可知
\[ \sigma(D_i) \sim |det J \boldsymbol{\varphi}(\xi_i)| \sigma(\Delta_i) \quad (i=1,2,\cdots, k) \]
所以得到
\[ \sum_{i=1}^k F(\boldsymbol{\eta}_i) \sigma(D_i) \sim \sum_{i=1}^k F \circ \boldsymbol{\varphi} (\boldsymbol{\xi}_i) |det J \boldsymbol{\varphi} (\boldsymbol{\xi}_i)| \sigma(\Delta_i) \]
当分割无限细时,由函数积分九的定理7可得,
\[ \int_D F \mathrm{d} \sigma = \int_\Delta F \circ \boldsymbol{\varphi} |J \boldsymbol{\varphi}| \mathrm{d} \sigma \]

Q.E.D.

定理7:极坐标换元

\(x = r \cos \theta, y= r \sin \theta\),则
\[ \iint \limits_D F(x, y) \mathrm{d} x \mathrm{d} y = \iint \limits_\Delta F(r \cos \theta, r \sin \theta) r \mathrm{d} r \mathrm{d} \theta \]

证:这时
\[ \frac{\partial(x, y)}{\partial (u, v)} = \left| \begin{matrix} \cos \theta & -r\sin \theta \\ \sin \theta & r \cos \theta \end{matrix} \right| = r \]
代入定理6的结果即证。

Q.E.D.